C Cerebral New Member Joined Jan 2, 2004 Messages 17 May 8, 2005 #1 I) Show that f(x) = e^x - 3x^2 has a root between x = 3.7 and x = 3.8. II) Starting with x = 3.8 use one application of Newtons to find a better approximation for this root.
I) Show that f(x) = e^x - 3x^2 has a root between x = 3.7 and x = 3.8. II) Starting with x = 3.8 use one application of Newtons to find a better approximation for this root.
Slidey But pieces of what? Joined Jun 12, 2004 Messages 6,600 Gender Male HSC 2005 May 8, 2005 #2 I) show that the sign changes from f(3.7) to f(3.8) II) x_2=x_1-f(x_1)/f'(x_1) Better estimate=new x=3.8-f(3.8)/f'(3.8) Recalling f'(x)=e^x-6x
I) show that the sign changes from f(3.7) to f(3.8) II) x_2=x_1-f(x_1)/f'(x_1) Better estimate=new x=3.8-f(3.8)/f'(3.8) Recalling f'(x)=e^x-6x
