Nnnnnnnnnnnoooo!!!!!!!!!!! (2 Viewers)

Finx

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Okay, I think you should just chillax Shoom. You should only react this way after a HSC exam.. Year 11 doesn't count for shit.
 

Shoom

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I might aswell post all my marks to give an indication of how ive been doing


Maths
19.5/34, 32/60, 19/25

Ex
13/30 27/52 13/35

Adv English
21/30 14/20 14/20

Chemistry
20/30 24/30 51/70 33/40

Physics
17/39 22/35 38.4/50

Biology
43/45 14/17 45/60

Sor1

20/25 10/15


Im going to blow all these exams for all subjects because I have not studiied, but so far what do you think of my marks?
 

Glass Prisoner

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lol, i love how everyone like assumed that the teachers took the questions all from the same past papers...
put it together guys, we is prob go to same school, i mean i know Shnurs and I do...
i put that together easy, cos PY is a terrible band *jks*, but seriously, do you peeps who all said 'i had that Q too' go to Smith's Hill per chance???
cos then it would all make sense, like it does in my head atm... if you dont, then the other theory is more than likely right

i have absolutely no recollection of what i did for that Q... all i know is that i completely forget how to figure out the equation of the normal... all I knew to get was the gradient... then i was stuffed... so i lost marks there

lol, but as peeps are saying, its only yr11 guys, prelim only counts if you're going for a job or scholarship straight after school =P
 

Finx

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Is Shnurs Venz or Amirt? I know Proust would be browsing the 4U boards if it was him.

Dapto and French Continuers? I can't figure out who you are.
 

Shoom

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Hey, if someone was going to get an N award will they have know by now? oh and gp I figured out the gradient and hence the equation wrong. Will I still get marks because I knew the method just put the wrong numbers?
 
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tommykins

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inconnuBubble said:
hrm...
are you people sure?
because i got 7.3428571428571428571428571428571m
...
or 7.34m (2 d.p.)

since
0.3=4.2% of original jump..
so
original jump=0.3/4.2*100
therefore needed distance = (0.3/4.2*100)+0.2m

?
O_O
You are correct.

Let i be initial jump, x = requirement

i = x - 0.2

1.042i = x + 0.1

x = i + 0.2

1.042i = i + 0.2 + 1
0.042i = 0.3
i = 50/7

50/7 = x - 1/5

x = 257/35m
 

untouchablecuz

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Shoom said:
Hey

Some athlete cant qaulify for long jump, its 0.2m less then the requirement, he improves his jump by 4.2% and its now 0.1m better then the requirement calculate the qualifying distance.
A-----------------x----------------C----------R--------D

Let distance AC (x) be his original crappy jump

Let R be the requirement

We know that his first jump was 0.2 less that the requirement

. ' . CR = 0.2

And that his second improved jump was 0.1 better than the requirement

. ' . RD = 0.1

Now, we are told that from he jumped 4.2% better than his initial jump (x) to reach D (4.2%*x = CD and CD = 0.2+0.1)

Solve 4.2%*x = 0.2+0.1 for x

x = 7.14

But we need to find AR (requirement), AR =AC + CR

i.e. AR = 7.14 + 0.2

AR = 7.34, i think

Anyone else get the same?
 

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