Objects thrown under free fall (1 Viewer)

[Not-That-Bright]

therefore you cannot determine the answer without knowing the hight of the cliff.

i think that it all makes sense...

The only problem I can see with the height is if it isn't high enough for the ball being thrown hits the ground too fast, but that wouldn't be anything you can call a 'cliff'.

 

[Mat_Aussie]

not-that-bright

do you agree with my answer?

 

[Not-That-Bright]

Well I don't think they have to reach terminal velocity.

 

[Mat_Aussie]

but without height of the cliff, the mass of the balls, and the force or speed at which they are thrown.

i dont think that it is possible to work it out, is it?

 

[Not-That-Bright]

Well I think we can assume that the cliff is fairy high, that the balls were thrown at a relatively normal throwing speed (i.e. not shot like a bullet) and are of average ball mass.... but that doesn't really matter.

 

[jyu]

This question is about objects thrown under free fall. Do you know the meaning of free fall?

 

[twilight1412]

the topic states freefall

BUT

in the question the person asked freefall is not mentioned

also i consider it illogical even by school standards for a situation to occur that involves freefall and a cliff

unless of course an elevator/car was pushed off and you were in it

 

[jyu]

Do you know the meaning of free fall?<!-- google_ad_section_end -->

 

[ianc]

everyone seems really confused here....

freefall (in the hsc sense of the word) is where the only force acting on an object is gravity - hence it is falling towards the earth.

The question does not need to specifically mention freefall - it is simply expected that at an hsc level you recognise that the only force acting on the object is gravity until it reaches the ground - so you apply the simple kinematics equations of v² = u² + 2as and v = u + at

do not worry about terminal velocites and all that for freefall (unless of course you're a 4unit maths student doing mechanics)

hope this has helped!