Official 2005 CSSA Trial Exam Thread (1 Viewer)

[!lukey!]

How did you do 10a?

the one simplifying the log?, u brought the 2ax to the front and the logee cancelled and u were left with just 2ax

 

[c_james]

Q1 i) was
l-6l-l-12l = ?

I put the possible answers as 6, -6, 18 and -18...is that wrong?

You're thinking of the numbers in terms of variables. There were no variables, hence only 1 answer.

 

[r.haidar]

How did you do 10a?

loge of e^2ax... bring the power down (log law) and u get 2ax loge of e

log e of e is just 1 so u get 2ax

then the integration is just

integral btwn 0 and a of 2ax
u get 2ax^2 / 2 which = [ax^2] (0 and a)

then u sub in values

and u get a^3

hope that helps

 

[evette13]

there were 4 yes, but 1 correct.... -6 lol

Hey How did u prove that that was correct?

 

[!lukey!]

Q1 i) was
l-6l-l-12l = ?

I put the possible answers as 6, -6, 18 and -18...is that wrong?

yeah i thought there was only one answer , -6 too...

 

[ar3nbe]

Makes me feel better, thats excalty what i got. Again, i was a little weary of the simplicity, considering it was qu 10a

 

[r.haidar]

Hey How did u prove that that was correct?

well |-6| = 6

and |-12| = 12

then its just 6 - 12

if it was = to x or something u could say there were multiple values for x... but they didnt ask that

 

[goan_crazy]

loge of e^2ax... bring the power down (log law) and u get 2ax loge of e

log e of e is just 1 so u get 2ax

then the integration is just

integral btwn 0 and a of 2ax
u get 2ax^2 / 2 which = [ax^2] (0 and a)

then u sub in values

and u get a^3

hope that helps

thanx r.haidar
I got 2ax
but not the rest
O well I'm happy, 1 mark in the hardest question is good

 

[laurel18]

well |-6| = 6

and |-12| = 12

then its just 6 - 12

if it was = to x or something u could say there were multiple values for x... but they didnt ask that

Exactly...they won't make the first question that hard anyways

 

[!lukey!]

well |-6| = 6

and |-12| = 12

then its just 6 - 12

if it was = to x or something u could say there were multiple values for x... but they didnt ask that

and to think that it was worth two marks too...

 

[switchblade87]

well |-6| = 6

and |-12| = 12

then its just 6 - 12

if it was = to x or something u could say there were multiple values for x... but they didnt ask that

WOOHOO! I've got at least 2 marks!

 

[goan_crazy]

well |-6| = 6

and |-12| = 12

then its just 6 - 12

if it was = to x or something u could say there were multiple values for x... but they didnt ask that

i got -6 for that absolute value one
2 marks

 

[r.haidar]

thanx r.haidar
I got 2ax
but not the rest
O well I'm happy, 1 mark in the hardest question is good

yuk!!! im a nerd!!! im helpin people ewwww i didnt think i would ever get this smart haha no worries! the names ralph. haidar hehe

 

[alex_london0]

same yesssssss......2/120

 

[know_it_all]

u 3uniters are freeking me out!
but i got sum of the answers ur talking bout!...so hopefullii im kina on track (doubtful, very doubtful)
neway..gluk every1 for the rest of ur trials

 

[goan_crazy]

r.haidar ...
Ralph Haider ay?
Thats a mad name!
You're a champ!
I wish I was as smart as u! lol
is that u in ur av?

 

[r.haidar]

u 3uniters are freeking me out!
but i got sum of the answers ur talking bout!...so hopefullii im kina on track (doubtful, very doubtful)
neway..gluk every1 for the rest of ur trials

i really doubt a question such as " 6 - 12 " would turn up in a 3 unit paper... i reeeeeeealy do haha

 

[r.haidar]

r.haidar ...
Ralph Haider ay?
Thats a mad name!
You're a champ!
I wish I was as smart as u! lol
is that u in ur av?

yes thats me in tha av hehe in my IPT class... and its haidAr (with an A) to correct ur error, sub in e=a and u would get haider=haidar

aaaaaaahhhhhhhhhh its happening! im nerdifiying!!!!!

 

[waterbottle]

urgh i think i fucked up the probability question, and the question with the shaded area. other than that it wasn't too difficult, though (and i only do 2u).

 

[laurel18]

yes thats me in tha av hehe in my IPT class... and its haidAr (with an A) to correct ur error, sub in e=a and u would get haider=haidar

aaaaaaahhhhhhhhhh its happening! im nerdifiying!!!!!

HAHAHAHAHAHA when you do too much maths...this is what happens...