Drsoccerball
Well-Known Member
- Joined
- May 28, 2014
- Messages
- 3,647
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- HSC
- 2015
I thought it would've been to prove that the equation of :Its obviously to prove:![]()
I thought it would've been to prove that the equation of :Its obviously to prove:![]()
That can't possibly be ask-able its too hard right? Even for a BOS trial.I thought it would've been to prove that the equation of :![]()
Isn't it defined by i^2=-1 rather than just i=(-1)^1/2 alone?
I havn't got mine eitherGetting curious now. It's this Friday. Have numbers or whatever been sent out?
Mine hasn't been sent.Getting curious now. It's this Friday. Have numbers or whatever been sent out?
Like all good maths teachers doCalm down guys, there is still 3 days left, carrot will probs give it out the night before
I just have one question for 2U IS MY MATE ACCEPTED D: i signed him up on my account?!?!I will be sending out the numbers tonight! Very excited for Friday.
To compensate for my delayed distribution of student numbers, I'll answer one question each about 2U/3U/4U.
But of course I won't be answering questions like "What's the last question proving?" etc.
Oooo, one question per person or one question overall per unit? Because if it is the latter then we all have to agree on one question to ask.I will be sending out the numbers tonight! Very excited for Friday.
To compensate for my delayed distribution of student numbers, I'll answer one question each about 2U/3U/4U.
But of course I won't be answering questions like "What's the last question proving?" etc.
One per subject.Oooo, one question per person or one question overall per unit? Because if it is the latter then we all have to agree on one question to ask.
One per subject.
Totes just ignored me ahahahah.I just have one question for 2U IS MY MATE ACCEPTED D: i signed him up on my account?!?!
Question for 4U: how many 'famous' mathematical theorems/proofs are proved in the exam? e.g. last year there was Gaussian integral, the year before (iirc) there was a proof for 1/1^2 + 1/2^2 + 1/3^2 +..... = (pi^2)/6One per subject.