Parabola 1 (1 Viewer)

[simon_hitchcock]

wat did everyone1 get for the area between the parbola and that line, i got 12

 

[bloodysunday]

i got 18...........

 

[Brad]

I got 18 too.... and something like 45 for the total area then 45-18 for the shaded area.

 

[simon_hitchcock]

damn it, there goes my 100/120

 

[nomz]

ok... i was way off... i got like 9.153 something

 

[Brad]

Yeah.... i was happy that i got very very neat numbers.....

 

[simon_hitchcock]

yeah i got i neat number 2 so i thought it was right but now its not looking good

 

[bloodysunday]

well if you got the method right for part v then at least you'll get some marks

 

[simon_hitchcock]

yeah i say i'll get some marks and hopefully it was a trascription error so i'll get full marks

 

[bloodysunday]

hehehe, yup we can only hope...

 

[smallcattle]

45 - 18 = 27

 

[simon_hitchcock]

45 - 18 = 27

was that 4 the second part

 

[myg0t]

The area of the parabola was 18 without doubt.

I used an orthodox method to try and calculate the shaded area, would of got it if not for a stupid error, but the shaded area was 27.

 

[simon_hitchcock]

thanx for yas help now i knowim wrong lol

 

[bloodysunday]

good i definitely got 2 marks then

 

[Owyn]

was it 45 solid number or rounded, i can't remember my area of the triangle but i do remember the area of the triangle was estimated for me, however the area between was 18

 

[matt_f64]

u didnt need to estimate the area of the triangle.. u no the base length using 2 points, and u no the equation of the tangent, so u can work out the perpendicular height and then find the area using A=1/2 x b x h

 

[Acid]

Sweet I got 45-18 = 27 too...w00t... it's just fucked how completely gay questions are worth so many marks and decent questions like that are worth barely any.

 

[garry]

everyone got 45-18 = 27 ? can someone tell me how? i stuffed this question up but i did it again after the exam and i got the answer 14 for part 2. I got 15 for the area of the triangle by using 1/2absinC

 

[chriscity1]

Heah I got 12 too. But I couldn't figure out how to get the area for the last bit. Thought I'd fing the area of a triangle, using didtance formula, and tan0=m for 1/2absinC

Ohh Boyy!