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Parametrics Question (1 Viewer)

Thread starter Shuuya
Start date Sep 25, 2016

Shuuya

Well-Known Member

Sep 25, 2016

MX1 HSC 2012 Question 12d) (i)

Thanks~

KingOfActing

lukewarm mess

Sep 25, 2016

$$In $\triangle ABC\\AC^2 + BC^2 = AB^2\\t^2+k^2 + y^2 + t^2 = y^2 + k^2 + 2ky\\ t^2 =ky\\y = \frac{t^2}{k}\\$As $OBPC$ is a rectangle, the coordinates of $P$ are$\\x_P = t, y_P = y = \frac{t^2}{k}$

braintic

Well-Known Member

Sep 26, 2016

Or just gradients:

-y/t times k/t = -1

y=t^2/k

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