Partial Fractions Q9 (1 Viewer)

KFunk

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1 = a(x<sup>2</sup> +1) +x(bx +c)
= (a +b)x<sup>2</sup> +cx +a

hence a+b=0, c=0, a=1 ---> b=-1 giving you:
&int; 1/x - x/(x<sup>2</sup> +1) dx

= lnx - 1/2ln(x<sup>2</sup> +1) + c
= ln [x/&radic;(x<sup>2</sup> +1)] + c
 

KFunk

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Perhaps this is a novel idea, but you could ask all of these questions in the one post?
 

want2beSMART

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that way it would hard to keep track of things...unethical
 

Slidey

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If you do, then explain how "not suiting you" correlates with 'unethical'.
 

dawso

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q 9, hm........i think u shoudl practice a bit more m8...
 

want2beSMART

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i assure you not

legal is not a bludge subject...all the acts and termology to learn

it could be a bludge subject if you are a bludger yourself...but then again you would be failing most other subjects too
 

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