Physical Geo. Apps. (1 Viewer)

[DJel]

Hello,

I am a bit stuck on part e in the following question. Also, I would prefer to solve the actual question on my own, so any hints on finding the distance traveled would be great.

http://imageshack.ushttp://img106.imageshack.us/img106/6269/questionpw0.png

Here is my working thus far (sorry for the dodgy scan)

http://imageshack.us/http://img257.imageshack.us/img257/8361/answeryv3.png

Thanks,

DJel.

 

[lyounamu]

Hello,

I am a bit stuck on part e in the following question. Also, I would prefer to solve the actual question on my own, so any hints on finding the distance traveled would be great.

http://img106.imageshack.us/img106/6269/questionpw0.png

Here is my working thus far (sorry for the dodgy scan)

http://img257.imageshack.us/img257/8361/answeryv3.png

Thanks,

DJel.

You use the table and add all the distances together.

 

[DJel]

You find the definite integral of 7+ 6t - t^2 from 0 to 4 to find the total distance.

Thanks heaps for that, however when I found the definite integral of h from 0 to 4 I got the solution 54 + 2/3 when the answer was 10. I found out that I needed to use the integral from 0 to 4 of the velocity (6-2t).

DJel.

 

[lyounamu]

I am sorry. My solution was incorrect as I should have put more restrictions.

I found the answer to be 10 as well. But I did not use any integral.

I just used the table like the followings

t=0, 1, 2, 3, 4, 5
h=7, 12, 15, 16, 15

Total distance = (12-7) + (15-12) + (16-15) + absolute value of (15-16)
= 5 + 3 +1 +1
= 10

EDIT: We can actually use the integral. But the reason why I got it wrong is that I didn't take the account of the initial height & added that as the total distance and that's why I got ridiculous number.

 

[DJel]

No worries. That's an interesting way of finding the distance as an alternative to using the velocity. Once again, thanks for the help.

DJel.

 

[Darrow]

Ohh, so its the velocity you integrate, just got a question like this as a part of my homework
Thanks!
Makes sense: Velocity is the rate of change of x, so by integrating with limits 0,4 we are saying how far its gone, just like finding the area of something


Cough...I knwo what Im talking about