Physics 2019 Sydney BOys (1 Viewer)

Interdice

Well-Known Member
Joined
Jun 24, 2021
Messages
522
Gender
Male
HSC
2023
I'm confused with this.

the weight force(mg) is going down. where as the centripical force is going towards the centre

so shouldn't the expression be

3040sin(15) = 9.8m

???
 

howcanibesmarter

Well-Known Member
Joined
Jun 3, 2023
Messages
777
Location
The North Pole
Gender
Female
HSC
2023
For uniform circular motion on a banked track, using a force diagram gives you:

Fc=mgsintheta
They gave you Fc, so rearranging for m is

m=Fc/(gsin15)
 

Interdice

Well-Known Member
Joined
Jun 24, 2021
Messages
522
Gender
Male
HSC
2023
I think I need to read teh textbook on this part of the syllabus. And ask teacher. Thnaks
 

liamkk112

Well-Known Member
Joined
Mar 26, 2022
Messages
685
Gender
Female
HSC
2023
shouldn't it be tan theta or is it small angle approx
 

wizzkids

Active Member
Joined
Jul 13, 2016
Messages
266
Gender
Undisclosed
HSC
1998
shouldn't it be tan theta or is it small angle approx
Yes, it should be tan θ.
I disagree with that equation given in the sample answer. The result is correct, but the equation is wrong.
Here is the free body diagram of the car. The car is subjected to just two forces, they are W the force of gravity and FN the normal force from the road. The net force is unbalanced, and this creates Fc the centripetal force that keeps the car in circular motion, even when the road has no sideways friction.banked.png
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top