Nolocked.on said:To find a horizontal point of inflexion, you solve for f''(x) = 0 and the root must also be a solution to f'(x) = 0.
Graceofgod said:I have a funny feeling you are asking the wrong question though. Are you sure it asked for the area of the major segment? Because if you have a sector OAB, and a chord AB forming a minor segment, then you are talking about something else...
is this also the case for the hsc exam?12o9 said:f''(x) = 0 , remember to show a change in concavity as some schools deduct marks for not showing it
yes u'll have to do that...obviouslym00 said:by showing a change of concavity I mean for example:
if they ask us to find a point of inflexion and it turns out to be (4,2) for example then to check for concavity you gotta prove that f'(3) and f'(5) are both negative or both positive (this proves that it is an inflexion point)
im just wondering if we have to do this in the HSC exam or is finding f''(4) = 0 enough?
are you bloody serious?Graceofgod said:Haha, as if they would be THAT pedantic... =S
Anyway, if there were standing points or other points of inflexion then you would differ the points obviously.
Otherwise it wouldn't be a problem.
no. u dont know its a point of inflexion just coz f''(x)=0m00 said:but the thing is if its f''(x) = 0 its an inflexion point, its like a rule.. there is never an occasion were it isnt, to my understanding i would understand if the question asked to prove it, but is it really necessary to do it when they don't ask specifically?
when asking to prove its a point of inflexion it isnt asking for horizontal or vertical point of inflexion.. just a point of inflexion so f''(x) = 0 should be sufficient ??
Errr...it's a point of inflexion if f''(x) = 0..Timothy.Siu said:no. u dont know its a point of inflexion just coz f''(x)=0
u mustn't have been taught properly...
nah its not e.g. y=x^4 doesn't have onetommykins said:Errr...it's a point of inflexion if f''(x) = 0..
ah shit yeah, my badTimothy.Siu said:nah its not e.g. y=x^4 doesn't have one