C conman Member Joined May 2, 2005 Messages 139 Location West of Sydney Gender Male HSC 2007 Feb 13, 2007 #1 Whe P(x) is divided by (x-2) and (x-3) the remainders are 4 and 9 respectively. What is the remainder when P(x) is divided by (x-2)(x-3)
Whe P(x) is divided by (x-2) and (x-3) the remainders are 4 and 9 respectively. What is the remainder when P(x) is divided by (x-2)(x-3)
P pLuvia Guest Feb 13, 2007 #2 Let the remainder be ax+b, where a and b are constants When x=2 2a+b=4 When x=3 3a+b=9 Find a and b a=5 b=-6 Therefore the remainder is 5x-6, so when P(x) is divided by (x-2)(x-3), the remainder is 5x-6 Last edited by a moderator: Feb 13, 2007
Let the remainder be ax+b, where a and b are constants When x=2 2a+b=4 When x=3 3a+b=9 Find a and b a=5 b=-6 Therefore the remainder is 5x-6, so when P(x) is divided by (x-2)(x-3), the remainder is 5x-6
C conman Member Joined May 2, 2005 Messages 139 Location West of Sydney Gender Male HSC 2007 Feb 13, 2007 #3 Thanks a lot
B bos1234 Member Joined Oct 9, 2006 Messages 491 Gender Male HSC 2007 Feb 13, 2007 #4 He took the remainder as ax+b because if A(x) is x^2 then the power of the remainder must be less that 2 Similarly if A(x) has a power of 5 R(x) must have a remainder of less than 5
He took the remainder as ax+b because if A(x) is x^2 then the power of the remainder must be less that 2 Similarly if A(x) has a power of 5 R(x) must have a remainder of less than 5
