zenger69
Bok Choyer
On a worksheet about photoelectric effect, it asks "Explain the purpose of the power supply as it is connected into this circuit.
So I was wondering to measure the photoelectric effect, why does there need to be a potential difference going across.
Doesn't the UV hit the emitter, the emitter releases electrons and thats the current.
So I was wondering to measure the photoelectric effect, why does there need to be a potential difference going across.
Doesn't the UV hit the emitter, the emitter releases electrons and thats the current.