Green Yoda
Hi Φ
- Joined
- Mar 28, 2015
- Messages
- 2,859
- Gender
- Male
- HSC
- 2017
We ALL ALREADY know.
And learn to adapt to different ways of writing the same thing
We ALL ALREADY know.
And learn to adapt to different ways of writing the same thing
For some reason I didn't get an answer of x=3 for the first one.Ans are (for v=v(x))
1. x=3
2. max occurs when a=0, e^x/2(cosx-sinx)=0...tanx=1,...x=pi/4
3. a. x''=-1024/(x^3) = pi/4
b. the particle slows down to x=8
a=a(x)
1.a. v=2e^(-x/2)
b. v approaches 0 (as in v arrow 0)
3. a. 4squrroot of pi/3
b. Squreroot of 2pi/3
I think it's the wrong answersFor some reason I didn't get an answer of x=3 for the first one.
Calm down man I was just reminding pplWe ALL ALREADY know.
And learn to adapt to different ways of writing the same thing
How about you stop worrying about other people's genders. THere's nothing interesting about it okayWell have you learnt pretty much all the other 2U topics? Cause motion is usually the LAST taught 2U topic
Also I'm teasing because Shuuya's handwriting was what sparked this whole debate and lead Nailgun to believing she was a guy
Shuuya did you get this right?
I haven't done itShuuya did you get this right?
Some more motion questions:
Motion defined by v=v(x)
2.The velocity of a particle moving on the x-axis is given by v= (squareroot of sinx) e^(x/2), 0≤x≤pi/3, where x is the displacement of the particle from the origin
a.Show that the acceleration of the particle in terms of its displacement can be expressed by a=1/2 e^(-x) (cosx-sinx)
b.Hence find the displacement of the particle at which the maximum speed occurs
Then you shouldn't worry about if she's done a topic either.How about you stop worrying about other people's genders. THere's nothing interesting about it okay
just to make sure she's doing it right (I still keep thinking Shuuya is a guy even though she's a girl)Then you shouldn't worry about if she's done a topic either.
It's okayOk I should apologise. There is the factor of hunger that's fueling my temper right now.
What's the question lol (are you asking for it to be simplified?)Help me with this easy question: sin2A/(1+cos2A)
yup I'm just a bit blind right now and can't seeem to figure it outWhat's the question lol (are you asking for it to be simplified?)
Help me with this easy question: sin2A/(1+cos2A)
Thanks Shuuya
Oops I got beaten