PROBABILITY HELP PLEASE! :( :( (1 Viewer)

fatima96

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This question is absolutely crappy. I can not do it :| And I have a test on Monday. BOSers, you are my only hope. Please help me out!
a) A poker machine with 3 wheels has 4 aces on the first wheel, 2 kings on the second and 3 Jacks on the third. In how many ways can the machine stop to show Ace, King, Jack?
b) If each of the three wheels has 10 symbols, how many total positions are possible & what is the probability for ace, king and jack?

T___________________________________T
 

dr cookie

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to be honest, i would just write:

I am morally and religiously opposed to gambling.

^_^ sorry i can't be of more help
 

dr cookie

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:p could it be like a factorial? I don't know, sorry... I'm woeful at maths to say the least!!!

during maths lessons: UM DA COW SAID MOOS?
 

fatima96

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i figured it out peopleee :|
for a)
you multiply the 4 aces by the 2 kings by the 3 jacks to give you all possible outcomes.
b)
10 X 10 X 10 = 1000, which gives total outcomes.
we know from a that the outcomes for the ace king and jack will be 24
so 24 over 1000 = 6/125.


just stressed for like an hour for this :|
 

Shadowdude

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i figured it out peopleee :|
for a)
you multiply the 4 aces by the 2 kings by the 3 jacks to give you all possible outcomes.
b)
10 X 10 X 10 = 1000, which gives total outcomes.
we know from a that the outcomes for the ace king and jack will be 24
so 24 over 1000 = 6/125.


just stressed for like an hour for this :|
You stressed for an hour...?

I knew probability was a weak point for some people but if it took you an hour to come up with that...

Take these probability questions logically, and you'll go far.
 

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