Probability Q (1 Viewer)

OL_O · Jul 25, 2015

a die is rolled twice and the numbers rolled are added together. A is the event "the sum is 4 or more" B is the event "the sum is less than 6" & C is the event "the 2 numbers rolled are the same"
Find:
i) P(A & B)

VBN2470 · Jul 25, 2015

The event $A \cap B$ denotes the event that the sum is 4 or more but is less than 6 i.e the sum can only be 4 or 5. This happens only when you land (1,3), (2,2), (3,1), (1,4) (2,3), (3,2), (4,1). Hence, $\mathbb{P}(A\cap{B})=\frac{7}{36}$ .

OL_O · Jul 25, 2015

VBN2470 said:
The event $A \cap B$ denotes the event that the sum is 4 or more but is less than 6 i.e the sum can only be 4 or 5. This happens only when you land (1,3), (2,2), (3,1), (1,4) (2,3), (3,2), (4,1). Hence, $\mathbb{P}(A\cap{B})=\frac{7}{36}$ .

oh ok i see what i did wrong
Thank you

Probability Q (1 Viewer)

OL_O

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VBN2470

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OL_O

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