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Probability question (1 Viewer)

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all the letters of the word ENCUMBRANCE are arranged in a line. Find the total number of arrangements, which contain all the vowels in alphabetical order but separated by at least one constant.
(JRAH 03 trial)
 

ngai

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this again...
hmm let me think wat i said last time...
ohh, i remember now:
88200 ways (by inspection)
 

Xayma

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Where you run over things in your head until you get the answer.
Also where they cant be bothered to post the working cause they did it on a calculator only
 

Rorix

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why bother you already know the answer :cool:
 

superbird

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ToO LaZy ^* said:
all the letters of the word ENCUMBRANCE are arranged in a line. Find the total number of arrangements, which contain all the vowels in alphabetical order but separated by at least one constant.
(JRAH 03 trial)
i think the answer is:
11!/2!2!
 

Managore

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Uhh just looking at the question now.. I think:

Replace the vowels with say X, their order is already determined so they don't have to confuse us.
Find out combos with Y(constanant)
eg YXYYXYXYYXY
( )xY( )xY( )xY( )x( ) the brackets can be filled with any number of Y's, having 4 left. = 5^4 I think... but that's wrong
Next, we have the order of Ys, or constanants.
7!/(2!x2!)
And that should give us an answer... but alas.. I've done something wrong. Help?
 

mojako

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do a search on this forum
theres this exact question before...
 

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