probability (1 Viewer)

[highkeydropout]

hi, does anyone know how to solve the following?

 

[jimmysmith560]

Do you have the answers to those by any chance?

 

[Trebla]

The probabilities for {1,2,3,4,5,6} are {x,x,x,x,x,2/3} where x is unknown. You can solve for x using the fact that sum of the probabilities across the entire sample space is 1.

Once you do that, you will have the full probability distribution and can answer the rest of the questions.

 

[Eagle Mum]

i) 1 in 3 probability of any number other than six.
ii) 1 in 3 probability in i) is split five ways with the other numbers, so (1/3) x (1/5) = 1/15 or 1 in 15 probability of rolling a ‘2’.
iii) 1 in 15 probability of rolling a ‘2’, 1 in 15 probability of rolling a ‘4’ and 2 in 3 probability of rolling a ‘6’. Therefore, probability of rolling an even number is 1/15 + 1/15 + 2/3 = 12/15 = 4/5 or 4 in 5.

 

[highkeydropout]

thank you all!