Pocatello said:
If all the letters making up the word Wollongong are placed in to a hat and drawn out, what is the probability of:
a) The word beginning with an 'o'
b) The word having no two identical letters in a row
c) At least one 'l' placed between the 'g''s
Thanks
interesting
part a)
3/10
part b)
prob of l's in a row
9/<sup>10</sup>C<sub>2</sub>
1/5
prob of g's in a row
9/<sup>10</sup>C<sub>2</sub>
1/5
prob of n's in a row
9/<sup>10</sup>C<sub>2</sub>
1/5
prob of o's in a row
71/<sup>10</sup>C<sub>3</sub>
71/120
prob of l's and g's
1/5 * 1/5
1/25
prob of l's and n's
1/5 * 1/5
1/25
prob of l's and 0's
1/5 * 7/120
7/600
prob of g's and n's
1/5 * 1/5
1/25
prob of g's and o's
1/5 * 7/120
1/600
prob of n's and o's
1/5 * 1/120
1/600
prob of l's and g's and n's
1/5 * 1/5 * 1/5
1/125
prob of l's and g's and o's
1/5 * 1/5 * 7/120
7/3000
prob of l's and o's and n's
1/5 * 1/5 * 7/120
7/3000
prob of o's and g's and n's
1/5 * 1/5 * 7/120
7/3000
prob of all
1/5 * 1/5 * 1/5 * 7/120
7/15000
ther fore prob of none
p = 1 - (1/5 + 1/5 + 1/5 + 7/120 - 1/25 - 1/25 - 7/600 - 1/25 - 1/600 - 1/600 - 1/125 - 7/3000 - 7/3000 - 7/3000 - 7/15000)
= 3691/7500
ther must be an eaier way to do it
part c)
i'l sleep on it