K Kostie100 Member Joined Mar 18, 2012 Messages 145 Location Sydney Gender Male HSC 2013 May 25, 2013 #1
J jmk123 New Member Joined May 25, 2013 Messages 26 Gender Male HSC 2013 May 25, 2013 #2 Kostie100 said: View attachment 28153 Click to expand... x''=0 x'=15sqrt2 x=15sqrt2t y''=-10 y'=-10t+15sqrt2 y=-5t^2+15sqrt2t When y=-10, t=4.67 (2dp) so time of flight=4.67s When t=4.67, x=99.08 (2dp), so distance travelled is 99.08m I think thats right.
Kostie100 said: View attachment 28153 Click to expand... x''=0 x'=15sqrt2 x=15sqrt2t y''=-10 y'=-10t+15sqrt2 y=-5t^2+15sqrt2t When y=-10, t=4.67 (2dp) so time of flight=4.67s When t=4.67, x=99.08 (2dp), so distance travelled is 99.08m I think thats right.
K Kostie100 Member Joined Mar 18, 2012 Messages 145 Location Sydney Gender Male HSC 2013 May 25, 2013 #3 jmk123 said: x''=0 x'=15sqrt2 x=15sqrt2t y''=-10 y'=-10t+15sqrt2 y=-5t^2+15sqrt2t When y=-10, t=4.67 (2dp) so time of flight=4.67s When t=4.67, x=99.08 (2dp), so distance travelled is 99.08m I think thats right. Click to expand... Yep thanks
jmk123 said: x''=0 x'=15sqrt2 x=15sqrt2t y''=-10 y'=-10t+15sqrt2 y=-5t^2+15sqrt2t When y=-10, t=4.67 (2dp) so time of flight=4.67s When t=4.67, x=99.08 (2dp), so distance travelled is 99.08m I think thats right. Click to expand... Yep thanks
