Projectile Motion Question (1 Viewer)

[namburger]

http://i237.photobucket.com/albums/ff3/Namburger/Projectilemotion.jpg

please include a diagram for me

 

[lolokay]

say the projectile starts at the origin and has moved to point (x,y)

y = g/2v²cos[a]² x² + tan[a] x (from basic projectile motion equation. derive if necessary)
y' = g/v²cos[a]² x + tan[a]

tan[@] = y/x
2y/x - tan[a] = g/v²cos[a]² x + tan[a]
so 2tan[@] - tan[a] = y' (the direction of motion)
= y'

 

[shaon0]

say the projectile starts at the origin and has moved to point (x,y)

y = g/2v²cos[a]² x² + tan[a] x (from basic projectile motion equation. derive if necessary)
y' = g/v²cos[a]² x + tan[a]

tan[@] = y/x
2y/x - tan[a] = g/v²cos[a]² x + tan[a]
so 2tan[@] - tan[a] = y' (the direction of motion)
= y'

At this rate, you'll come 1st in the state in MX2 lol.

 

[tommykins]

回复: Re: Projectile Motion Question

At this rate, you'll come 1st in the state in MX2 lol.

That's what I PM'd him about. haha.

 

[shaon0]

Re: 回复: Re: Projectile Motion Question

That's what I PM'd him about. haha.

Well its true.

 

[namburger]

Thanks lolokay

You got 1 year of revision. Top in MX2 for sure =O

 

[shaon0]

Thanks lolokay

You got 1 year of revision. Top in MX2 for sure =O

Unless some olympiad guy beats him.