J jskeza Member Joined Aug 8, 2019 Messages 76 Gender Male HSC N/A Oct 28, 2019 #1 I know how to do this but I don't understand why the roots of the equation gt^2 - 2Vtsinθ + 2h = 0 give t1 + t1 and t1t2. Can someone please explain why it works. Thanks
I know how to do this but I don't understand why the roots of the equation gt^2 - 2Vtsinθ + 2h = 0 give t1 + t1 and t1t2. Can someone please explain why it works. Thanks
Trebla Administrator Administrator Joined Feb 16, 2005 Messages 8,392 Gender Male HSC 2006 Oct 28, 2019 #2 When you solve that quadratic equation in terms of t, you are effectively finding the times where y=h
When you solve that quadratic equation in terms of t, you are effectively finding the times where y=h
J jskeza Member Joined Aug 8, 2019 Messages 76 Gender Male HSC N/A Oct 28, 2019 #3 Trebla said: When you solve that quadratic equation in terms of t, you are effectively finding the times where y=h Click to expand... thanks! i was thinking h was max height, now i took a another look at the diagram it makes sense. it was a really stupid question after i saw it lol
Trebla said: When you solve that quadratic equation in terms of t, you are effectively finding the times where y=h Click to expand... thanks! i was thinking h was max height, now i took a another look at the diagram it makes sense. it was a really stupid question after i saw it lol