Proofs (1 Viewer)

kractus

Member
Joined
Jan 4, 2023
Messages
64
Gender
Male
HSC
2024
Screen Shot 2023-02-11 at 8.54.52 pm.png
How would you do both these questions? I don't know where to start
 

011235

Active Member
Joined
Mar 6, 2021
Messages
207
Gender
Male
HSC
2023
Q14 (a)

Let n=2k+1 (odd) where k is a positive integer.

Let n consecutive numbers be a+1, a+2, a+3, ..., a+n for some integer a.

The sum of these is;



Hence the sum is divisible by n.

Now try using the same logic for (b)
 

jimmysmith560

Le Phénix Trilingue
Moderator
Joined
Aug 22, 2019
Messages
4,550
Location
Krak des Chevaliers
Gender
Male
HSC
2019
Uni Grad
2022
Would the following working help with Question 15?

Let the digits of a 4-digit number n be a, b, c, d.

That is,







Part 1:

If n is divisible by 3, then for some integer m.

Therefore:





Therefore the sum of the digits (𝑎 + 𝑏 + 𝑐 + 𝑑) is a multiple of 3.

Part 2:

If the sum of the digits is a multiple of 3, then (𝑎 + 𝑏 + 𝑐 + 𝑑) = 3𝑘 for some integer 𝑘.

Therefore:





Therefore 𝑛 is divisible by 3. We have now proved the result in both directions, so a 4-digit number is divisible by 3 if and only if the sum of its digits is divisible by 3.
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top