Q! (1 Viewer)

[Sirius Black]

The 4-digit number 2652 is such that anyu two consecutive digits from it make a multiple of 13. Another number N has the same property but with 100 digits, and begins with 9. what is the last digit of N?
choices: (a)2 (b)3 (c)6 (d) 9
N= 913913913.... SO the answer is d?
thanx in advance

 

[Riviet]

Lol, this sounds like one of those questions that you get in the maths comp.

d i think is right but...

There may be more than 1 right answer???

 

[insert-username]

As far as I can tell, D would be correct.


I_F

 

[KeypadSDM]

Only 1 solution:

9 must be followed by a 1, 1 must be followed by a 3, 3 must be followed by a 9. And the cycle continues.

 

[Riviet]

Ah... that makes sense.