question 10 a) (1 Viewer)

[simon_hitchcock]

what was the deal, did part 2 actually have anyhthing to do with part 1

 

[lucyinthehole]

yeah. costan = sin so you could reduce the 2nd equation to sin^2

 

[myg0t]

i think your talking about 9a lucy.

i was thinking the same thing, i got a but not b and i know it was soemthign stupid. but then again i had about 5 mins to do q10

 

[sneeble]

Err, wrong q lucy.

If you're talking about 10)a)i) and ii), here's the connection;

The integral of 1/x is Lnx, between a and 3a comes out to Ln3 (using log laws). The estimation using the simpsons rule was for the same area (a to 3a), hence Ln3 is approximately equal to 10/9.

Stupidest question 10 I've ever seen. Question 9 was harder.

 

[lucyinthehole]

ah crap yes sorry, i shoulda checked the paper, not relied on my memory....

 

[bloodysunday]

Stupidest question 10 I've ever seen. Question 9 was harder.

Again, i disagree - 9 was plenty easy, limiting sum, accel graph and a function... no probs; but this totally abstract cosine thing? agh, if i knew then what i know now...

 

[DeadFish]

Err, wrong q lucy.

If you're talking about 10)a)i) and ii), here's the connection;

The integral of 1/x is Lnx, between a and 3a comes out to Ln3 (using log laws). The estimation using the simpsons rule was for the same area (a to 3a), hence Ln3 is approximately equal to 10/9.

Stupidest question 10 I've ever seen. Question 9 was harder.

He's right on the money

I expected MUCH more from a q10.

 

[garry]

i think i stuffed this question, for part 2 i just let a=1 so it connects

 

[Sweet_Lemon]

sure they connect~~

 

[JayWalker]

I was expecting such a harder quetsion 10, I was sort of dissapointed

 

[LozziPozzi]

Hey, what was the answer for q10 part a (i)....were you meant to get liek a quadratic?
I was going sweet until halfway thru q9...goddamit.

 

[bevstarrunner]

if u did it right, 10a)i) should be 10/9, hence the link to the next question

 

[username]

i got 10/9a???? how did u get rid of the a

 

[Sweet_Lemon]

the a should cancel with 1/3a.... something like tat...can't remeber~

 

[bevstarrunner]

A = a/3 (1/a + 1/3a + 4(1/2a))
= a/3 (1/a + 1/3a + 2/a)
= 1/3 + 1/9 + 2/3
= 10/9

 

[LozziPozzi]

A = a/3 (1/a + 1/3a + 4(1/2a))
= a/3 (1/a + 1/3a + 2/a)
= 1/3 + 1/9 + 2/3
= 10/9

i got up to the second line...dammit i screwed up in the working out.