#### ToRnaDo

##### Member

h = v^2sin^2 a / 2g and x = v^2 sin2a /g

should notice that the maximum height in part iii) is H-S = h

soo H-S = v^2 sin^2 a/ 2g (1) and d= v^2 sin2a/g

= 2v^2 sina cosa/g

--> d^2 = 4 v^4 sin^2 a cos^2 a / g^2 (2)

sub (1) into (2) to withdraw v^2 cos^2 = something

And from (1) again to withdraw v^2 sin^2 = somthing

Using fact that sin^2 + cos^2 = 1 to add them together

Should end up with equation relative to d and (H-S) and find out result easily..... That what i think the answer will be

Just give me 10 minutes more ..... but actually i lost about 7 marks for silly mistake and included the 4 marks question 7 iii)

Grrrr Hope i still get in band 6. I already did badly in 4 Units> Soo please BOS ..Don't find our any more my silly mistake