Nah, i made up some random equation.rooeys2 said:lol nam did you do it?
amphoteric > amphiprotic so anything amphiprotic are classified under amphoteric.
you react lead oxide with water and hydrochloric acid to show its acidic and basic nature, i rkn it was a pretty dodgy question
http://en.wikipedia.org/wiki/Lead_dioxideLead dioxide is amphoteric. Lead dioxide can dissolve in strong base to form plumbate ion, Pb(OH)6 2−. This can then form plumbate compounds. In acid conditions, it is typically reduced to lead(II) ion, Pb2+; lead(IV) ion, Pb4+, is not found in aqueous solution.
But firstly, H2O is neither an acid nor a base. I know that under some conditions it can be regarded as a Bronsted-Lowry acid or base, but I don't think that applies here. How can you have 2 substances that are amphiprotic to react? I don't know any extra-curricular stuff, but I just reckon that equation looks wrong. Especially the electrons. I don't recall any acid/base reactions having to deal with electrons.Azreil said:Lead (IV) oxide is PbO2, just so you know.
Closest I could come up with was:
PbO2 (s) + H2O (l) + 2 e- --> PbO (s) + 2 OH- (aq)
Not sure about with HCl.
shit did the question say lead (IV) oxide? cuz i wrote PbO, im pretty sure it was lead (II) oxide =S dont scare me!namburger said:Nah, i made up some random equation.
Could you write your equations, i checked wiki and it gave me this:
Still reckon its out of syllabus.
- with acid: PbO + 2HCl → PbCl<SUB>2</SUB> + H<SUB>2</SUB>O
- with base: PbO + Ca(OH)<SUB>2</SUB> +H<SUB>2</SUB>O → Ca<SUP>2+</SUP>[Pb(OH)<SUB>4</SUB>]<SUP>2-</SUP>