MedVision ad

question on increasing function (1 Viewer)

cossine

Well-Known Member
Joined
Jul 24, 2020
Messages
628
Gender
Male
HSC
2017
hmm i tried a few times still not sure how to do it, don't we find the domain of g(x) and intersect with domain of f(g(x))?
So you have been given the domain of g. When it say map [1, 4] to [2, 6] this means [1, 4] is the domain and [2, 6] is the range of g. Actually the question does not explicitly state the domain of g but without making that assumption the question is not doable.
 

SadCeliac

done hsc yay
Joined
Sep 23, 2021
Messages
2,516
Location
Sydney <3
Gender
Male
HSC
2023
Where are you guys getting these random proof questions 😭 I stg I'm doing all these and everything is all normal and then I come on here and you have these wack ass questions 😭😭😭
 

mathsbrain

Member
Joined
Jul 16, 2012
Messages
162
Gender
Male
HSC
N/A
So you have been given the domain of g. When it say map [1, 4] to [2, 6] this means [1, 4] is the domain and [2, 6] is the range of g. Actually the question does not explicitly state the domain of g but without making that assumption the question is not doable.
So we are looking for domain of f(g(x)), x values of g only makes sense if x values are within 1 to 4.
then f takes the y values of g as its x values, which means f takes values between [2,6] but domain of f is [0,5], so surely that means f takes values from 2 to 5? so I'm not sure how you are getting 3.5?
 

cossine

Well-Known Member
Joined
Jul 24, 2020
Messages
628
Gender
Male
HSC
2017
So we are looking for domain of f(g(x)), x values of g only makes sense if x values are within 1 to 4.
then f takes the y values of g as its x values, which means f takes values between [2,6] but domain of f is [0,5], so surely that means f takes values from 2 to 5? so I'm not sure how you are getting 3.5?
No, you want find {x : 0<= g(x) <= 5}. Notice x = 3.5 satisfies the condition.

#so surely that means f takes values from 2 to 5? so I'm not sure how you are getting 3.5?
This is not what the question is asking. When we consider domain we need to consider values of x not g(x).
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top