I'm pretty sure that since there is 2L of both SO2 and H2S, and they have different molar ratios, H2S becomes the limiting reagent. There would be 0.044 moles of SO2 leftover because 0.088 moles of H2S and 0.044 moles of SO2 is used up in the reaction.
Therefore, 3 x 0.044 = 0.132 moles of Sulfur is produced.
Mass of sulfur = Molar mass x moles of sulfur = 32.07 x 0.132 = 4.23324g