Questions on Binomial Probability (1 Viewer)

Dimsimmer

Random User
Joined
Sep 16, 2004
Messages
254
Gender
Male
HSC
2006
1. A die is loaded such that in 10 independent trials the probability that an even number appears 5 times is twice the probability that an even number appears 4 times. What is the probability that an even number in a single trial?

2.The probability that persons aged 60 and 65 will survive the next year is 0.97 and 0.96 respectively. From a group of five people of whom three is aged 60 and two aged 65, what is the probability that (i) not more than one will die within the next year, (ii) the two aged 65 will survive and not more than one does within the next year?

3.In an examination consisting of ten true-false questions, a student guesses the answers. What is the probability that he will gain 70% or better?

Thanks guys for your help.
 

Riviet

.
Joined
Oct 11, 2005
Messages
5,593
Gender
Undisclosed
HSC
N/A
3. p(70% or better)=p(70%) + p(80%) + p(90%) + p(100%)
=(10C7)/210 + (10C8)/210 + (10C9)/210 + (10C10)/210
=0.17 (2 dp)
 

webby234

Member
Joined
Nov 14, 2005
Messages
361
Gender
Undisclosed
HSC
N/A
1. Let a be the probablity an even number appears in an independant trial and b be the probability of an odd number.

(a + b)10
= a10 + ... + 10C4 a4b6 + 10C5 a5[/sup[bsup]5...+ b10

10C5 a5b5 = 2*10C4 a4b6

3a = 5b
a + b = 1 (as a and b are the only two possibilities)

3 - 3b = 5b
b = 3/8
a = 5/8
 

gamecw

Member
Joined
May 5, 2006
Messages
242
Gender
Male
HSC
2006
2. (i) not more than one will die within the next year

60 die - 0.03, 65 die - 0.04

not more than one will die:
1. 1 of 60 dies, 65 all live
2. 1 of 65 dies, 60 all live
3. all live!

1. 3C1 x (0.97^2) x (0.03) x (0.96^2) = 0.078
2. (0.97^3) x 2C1 (0.96) (0.04) = 0.07
3. (0.97^3) (0.96^2) = 0.841

Therefore, prob = 0.078+0.07+0.84 =0.989

mm i think..

Edit:
hey part two of 2 doesnt make sense to me
(ii) the two aged 65 will survive and not more than one does within the next year?

If the statement already says two will survive, then how to work out 'not more than one does (surrvive)' for it? unless its a typo its 'dies' or not 'does'?

If im right then for (ii):

Prob = 0.078 + 0.841 = 0.919
 
Last edited:

Dimsimmer

Random User
Joined
Sep 16, 2004
Messages
254
Gender
Male
HSC
2006
Yeh part (ii) of two was a typo. Its actually 'dies', not 'does' so you are right.
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top