quick question on applications of calculus. (1 Viewer)

[theodore223]

should be an easy question, but hitting a mental blank;

Formula for acceleration for a particle is given by

A=5x - e^2x + 3,

where x is the displacement of the particle. If the acceleration of the particle is a constant -9.8 ms^-2, find the rate of change of its displacement when its displacement is -0.3 m?

(from Maths in Focus, Book 2, 6.2 question 10)
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[ssglain]

dA/dx = 5 - 2e^2x

dA/dt = -9.8

From these obtain dx/dt. Substitute x = -0.3.