E Ellie999 Member Joined Apr 17, 2007 Messages 37 Gender Female HSC 2007 Jun 12, 2007 #1 help im stuck.. i'll give you a prize if you can give me explanations and solutions to these Q's below... Differentiate the following with respect to x: 1. Sin^3x 2.Cos^2 2x thanks v.v. much in advance
help im stuck.. i'll give you a prize if you can give me explanations and solutions to these Q's below... Differentiate the following with respect to x: 1. Sin^3x 2.Cos^2 2x thanks v.v. much in advance
W webby234 Member Joined Nov 14, 2005 Messages 361 Gender Undisclosed HSC N/A Jun 12, 2007 #2 Use the chain rule: [f(x)]n = n[f(x)]n-1*[f'(x)] This means; multiply by the power, reduce the power by 1, then multiply by the derivative of the function. 1. sin3x = (sinx)3 d/dx = 3sin2xcosx 2. cos22x = (cos(2x))2 d/dx = 2(cos2x)1*-2sin2x = -4sin(2x)cos(2x)
Use the chain rule: [f(x)]n = n[f(x)]n-1*[f'(x)] This means; multiply by the power, reduce the power by 1, then multiply by the derivative of the function. 1. sin3x = (sinx)3 d/dx = 3sin2xcosx 2. cos22x = (cos(2x))2 d/dx = 2(cos2x)1*-2sin2x = -4sin(2x)cos(2x)
E Ellie999 Member Joined Apr 17, 2007 Messages 37 Gender Female HSC 2007 Jun 12, 2007 #3 ohh i get it now!!!! thanks webby!
i'll give you a prize if you can give me explanations and solutions to these Q's below...