Rates and Change Calculus Problem (1 Viewer)

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the only step that that solution doesnt show is
dA/dt=dA/dr*dR/dt

so basically u wanna find dA/dt
u know dR/dt=2 (given)
What's dA/dr?
Find A as function of r. In this case, its area(A)=pi*r^2
dA/dr=2pi*r

2pi*r * 2
=2*pi*10*2 (where r=10, given)
=40pi m^2/s (don't forget to put units with answer)

edit:
oops i realise now u only wanted to know why dR/dt=2.
You'll find that wiv these rates of change questions that you're usually given some data. just use it.
 
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acmilan

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Isnt that a extension 1 method?
Their radii increase at 2 m/s therefore the rate at which the radius is increasing with respect of time is 2 so dR/dt = 2
 
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Lazarus

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It certainly is just given to you, as acmilan1987 said.

"Their radii increase at the rate of 2m/s."

a) You know that the radius is changing at a rate of +2 metres per second.
b) dR/dt is the rate at which R (the radius) is changing with respect to t (time).

Therefore dR/dt = 2.

It's important to understand what you're actually doing (i.e. what the rates and the notation 'dy/dx' truly mean) if you want to be able to access the top mark range in the exam. Rote-learning and memorisation just don't cut it. You want to understand. :)
 

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