For C:

the equation would be P=1000e^(1/10*ln(2.5)t

so you would simply to substitute t =23 since 1995 is start and 2018 is what you're finding (2018-1995) = 23 yrs into the equation to find P:

P = 1000e^(23/10*ln(2.5))

= 8227.388777

therefore 8230

For e:

You use the value you get in d and then you would input that t value (t=25) into the differential equation dP/dt which would be k(1000e^(kt)) or kP and then you would just calculate the value of the rate of change.

dP/dt = k(1000e^25k) = 905

My maths might be a bit dodgy since its 11 here so I think someone here else could format this more nicely.