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Really Easy Motors + Generators Question (I can't do) (1 Viewer)

User-Dependent

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I can't work the following out, any help is appreciated;

A conductor carrying 2.5A experiences a force of .6N when .4m of its length is placed in a magnetic field of intensity 0.5T.

Calculate the angle the conductor makes with the field;

The supplied answer is 17.45 degrees.

I know it involves the F = BILsin(theta) equation, sadly I can't find theta.
 

tommykins

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回复: Really Easy Motors + Generators Question (I can't do)

Weird, i get sin@ = 6/5 and can't inverse it.
 

User-Dependent

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Re: 回复: Really Easy Motors + Generators Question (I can't do)

tommykins said:
Weird, i get sin@ = 6/5 and can't inverse it.
Same. I don't think you can shift sine a number over 1 (which unfortunately is 6 / 5).

17.5 degrees doesn't even get the same answer (.6N).

Maybe this question was a mistake.
 
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tommykins

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回复: Re: 回复: Really Easy Motors + Generators Question (I can't do)

User-Dependent said:
Same. I don't think you can shift sine a number over 1 (which unfortunately is 6 / 5).

17.5 degrees doesn't even get the same answer (.6N).

Maybe this question was a mistake.
Yeah, it's not within the domain of the asin curve.

Best bet is the question is wrong.
 

Riet

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Re: 回复: Re: 回复: Really Easy Motors + Generators Question (I can't do)

Yep the question must be wrong.
 

chook 05

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maybe its to do with that ASTC circle used in maths?

like sin(@) = sin(360+@)

lol try that
 

obimoshman1234

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could u mabye post actual uestion up like so i can see how its worded and stuff also are u 100% sure those are the given values like u have put the right measurments for them???

cause if so no way that can work out
 

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