Reduction of water (1 Viewer)

[samwell]

is the following eqn possible for the reduction of water:
4H2O+electron =4OH- + 4H+ $@mu-l

 

[twilight1412]

i dont think its considered reduction
but then again i havent done this in a while
as far as i know its the ATOMS which are reduced/oxidised and not the molecule as a whole?

anyway
reduction is where the valance changes/becomes more negative
but the valence of H is still +1
and the valence on 0 is still -2

 

[samwell]

True dat i dont know wat i waz thinking. this is more of electrolysis dan reduction. i may lose 1 mark 4 it
tnks

 

[xiao1985]

2H2O + 4 e- + O2 ---> 4OH-

^ reduction of water.

 

[twilight1412]

so you can reduce molecules
ok then thanks duckie

 

[Forbidden.]

2H2O + 4 e- + O2 ---> 4OH-

^ reduction of water.

2H₂O + 4e^- + O₂ ---> 4OH^-

Fixed.

 

[YannY]

Haha you know what? you guys did a oxidation of water.

2 H2O + H2 -> 2 H3O+

That is the reduction of water.

2H<SUB>2</SUB>O + 4e<SUP>-</SUP> + O<SUB>2</SUB> ---> 4OH<SUP>- </SUP>
is oxidation of water as indicated by the - which shows a gain of electron.

 

[independantz]

Haha you know what? you guys did a oxidation of water.

2 H2O + H2 -> 2 H3O+

That is the reduction of water.

2H<SUB>2</SUB>O + 4e<SUP>-</SUP> + O<SUB>2</SUB> ---> 4OH<SUP>- </SUP>
is oxidation of water as indicated by the - which shows a gain of electron.

Umm, Oxidation is loss? 0_0

 

[Forbidden.]

Umm, Oxidation is loss? 0_0

I thought so.

 

[GMK]

The whole oil rig thing-Oxidation is loss of electrons, Reduction is gain of electrons. i.e. oxidation reduces the charge and reduction increases the charge.

 

[twilight1412]

^ the first part of your post is correct but the second part is wrong

because electrons have NEGATIVE CHARGE
a gain in electrons lowers the charge

 

[xiao1985]

2H₂O + 4e^- + O₂ ---> 4OH^-

Fixed.

bah, picky

 

[Undermyskin]

2H2O + 4e- + O2 ---> 4OH-

LOLZ. This is the reduction of water! It's not wrong! OILRIG. Reductant like alkali metals become oxidized and have + signs. Thus, the reverse is the reduction equation, gaining e-...

 

[cameron0110]

The reduction of water is actually 2H2O +2e- => H2 + 2OH- because one hydrogen in each water goes from oxidation state 1+ to 0. In the other equations that have been written, its actually the oxygen that is being reduced.

The first equation (H2O => H+ + OH-) isn't actually a redox equation at all if you check the charge balance, its the self-ionisation of water.

The best way to think about oxidation/reduction is using the oxidation state because if something is oxidised the oxidation state increases and if its reduced the oxidation state is reduced.

 

[xiao1985]

The reduction of water is actually 2H2O +2e- => H2 + 2OH- because one hydrogen in each water goes from oxidation state 1+ to 0. In the other equations that have been written, its actually the oxygen that is being reduced.

The first equation (H2O => H+ + OH-) isn't actually a redox equation at all if you check the charge balance, its the self-ionisation of water.

The best way to think about oxidation/reduction is using the oxidation state because if something is oxidised the oxidation state increases and if its reduced the oxidation state is reduced.

oops my bad...

i automatically linked reduction of water with shipwrecks

you are right, reduction of water forms H2 gas.