revenge of the integrals (1 Viewer)

[appleblossom]

Just when I thought I was getting good at integration and logarithms, I encountered this question:

Find indefinite integral of 3^(2x-1)

I'm sure the method wil turn out to be quite simple-- I just want to know how to get to the solution [3^(2x-1)]/2ln3. Any help would be greatly appreciated!

 

[pLuvia]

y=3^2x-1
=e^ln32x-1

Can you do it from there

 

[appleblossom]

grrr... I knew it would turn out to be simpler than I thought.
maybe next time I'll go back and look at the definition of a logarithm before asking stupid questions.
Thanks!