S1/17 WAM Predictions (3 Viewers)

[leehuan]

Lol didnt realise that you could only get a whole number

I'm not sure how it works at MQ, but at UNSW whole number marks is the norm and an effort will be made to round marks up where necessary. This may be different at MQ due to the use of the GPA and a focus on whether or not you got HDs/DNs/CRs instead of a number, but you should keep this into consideration when judging WAMs.

 

[Randox]

Ok guys would love some help here. Old wam was 73.958 with 24 subjects counted. New wam is (using wam glitch) 73.462. Anyone know how many subjects have been added from this semester for me so far?

 

[InteGrand]

Ok guys would love some help here. Old wam was 73.958 with 24 subjects counted. New wam is (using wam glitch) 73.462. Anyone know how many subjects have been added from this semester for me so far?

I will make the assumptions that all subject marks are whole numbers and all subjects are equally weighted. (If these assumptions don't both hold, you would have to provide us with what assumptions to use I suppose.)

The fractional part of the new Average is 0.462 (at least to three decimal places). This implies the total no. of subjects N (which is at least 25) cannot be 25, since the possible fractional parts then are precisely of the form k/25 (k an integer from 0 to 24), which would make the fractional part be a multiple of 1/25 = 0.04, and hence have a third decimal place of 0.

Note that 12/26 = 0.46153..., which is 0.462 to three decimal places, so 26 is a candidate for the total no. of possible subjects used.

Play around with your calculator on other numbers like 27 and 28 and see what the fractional parts around 0.4 are like for those numbers (so numbers of the form k/27 or k/28 that just less than 14/27 or 14/28), and see if any are 0.462 to three decimal places. If none are, 26 is probably the total no. of subjects used in the new Average.

 

[Queenroot]

y'all just wait until results come out

if u put this much effort into studyin y'all wouldn't have to worry about analysing ur damn WAM

 

[BenHowe]

The total of n integers will have a remainder of either 0, 1, 2, 3, …, or (n-1) upon division by n. This implies that the possible fractional parts for the average of n whole numbers are just: 0, 1/n, 2/n, 3/n, …, (n-1)/n.

E.g. If 1 subject: only can have decimal of 0.

If 2 subjects: only can have decimal of 0 or 0.5 (i.e. 0 or 1/2).

If 3 subjects: only can have decimal of 0, 0.333..., or 0.666..., (i.e., 0, 1/3, or 2/3).

If 4 subjects: only can have decimal of 0, 0.25, 0.5, or 0.75 (i.e. 0, 1/4, 2/4, or 3/4).

Etc.

Furthermore, if 0 < f < 1 and the smallest positive integer for which f occurs as a possible fractional part in the average is n₀, then f can occur as a fractional part in the average of N subjects (N a positive integer) if and only if N is a (positive) multiple of n₀ (easy exercise).

So for instance, a fractional part of 0.25 in the average means the no. of subjects used in the average must have been some multiple of 4, since 4 is the smallest positive integer for which 0.25 can occur as a fractional part.

(Assumptions: weights in the average are equal and subject marks are whole numbers. If one or more of these assumptions is violated, then other decimal values may be possible.)

Lol I think only people on BOS would have debate over this lol

 

[Randox]

I will make the assumptions that all subject marks are whole numbers and all subjects are equally weighted. (If these assumptions don't both hold, you would have to provide us with what assumptions to use I suppose.)

The fractional part of the new Average is 0.462 (at least to three decimal places). This implies the total no. of subjects N (which is at least 25) cannot be 25, since the possible fractional parts then are precisely of the form k/25 (k an integer from 0 to 24), which would make the fractional part be a multiple of 1/25 = 0.04, and hence have a third decimal place of 0.

Note that 12/26 = 0.46153..., which is 0.462 to three decimal places, so 26 is a candidate for the total no. of possible subjects used.

Play around with your calculator on other numbers like 27 and 28 and see what the fractional parts around 0.4 are like for those numbers (so numbers of the form k/27 or k/28 that just less than 14/27 or 14/28), and see if any are 0.462 to three decimal places. If none are, 26 is probably the total no. of subjects used in the new Average.

Thanks for this. I think it's 26. So 2 counted

 

[eating]

y'all just wait until results come out

if u put this much effort into studyin y'all wouldn't have to worry about analysing ur damn WAM

I study my WAM so that I can get a better WAM.

 

[4025808]

Maths results will be out tomorrow, I think.

 

[arob259]

Maths results will be out tomorrow, I think.

Fark, i hope.

 

[leehuan]

Maths results will be out tomorrow, I think.

Good. I'm getting impatient as hell.

y'all just wait until results come out

if u put this much effort into studyin y'all wouldn't have to worry about analysing ur damn WAM

Can't say I didn't try to.

 

[noctua]

Maths results will be out tomorrow, I think.

Do you check MATH results on the math mark page?

 

[Squar3root]

Do you check MATH results on the math mark page?

Yes those are your preliminary marks. Most of the time they don't change

 

[mreditor16]

ACTLs been uploaded to stream declaration

 

[Esse]

I have a number now. I did ENGG1000, ENGG1811, PHYS1121, MATH1131. Not sure which

Edit: I am 90% sure it's ENGG1811

 

[leehuan]

MATH is currently being logged in now I believe

 

[RenegadeMx]

MATH is currently being logged in now I believe

yeh has blank screen atm, exciting stuff

 

[DatAtarLyfe]

Keep us updated

Sent from my SM-G930F using Tapatalk

 

[malcolm21]

Something just got updated for me, guessing maths

 

[RenegadeMx]

maths is out

 

[RenegadeMx]

holy fuck he must have scaled hard if i got HD in foundations of calc LOL