Section I - Multiple Choice (1 Viewer)

[TheOptimist]

question 3 is A..
isn't it? conjugate base of z would be in the 4th quadrant? so multipy by 1 means it's in the first? O.O

this is mathematics 2u lol wrong thread

 

[scarvesss]

Here are the correct answers;
1)B
2)D
3)C
4)A
5)C
6)D
7)C
8)A
9)B
10)B
had this cross checked with my friends

i got the same

 

[freeeeee]

question 3 is A..
isn't it? conjugate base of z would be in the 4th quadrant? so multipy by 1 means it's in the first? O.O

I dont understand what you just said haha

 

[Timske]

wow i was expecting q10 to trick alot of people...

 

[habitres]

I can believe I got the tan one wrong. quite annoying. but yea rest seemed right I got 8A also *just sub in x=1
9/10 for that

 

[Timske]

I can believe I got the tan one wrong. quite annoying. but yea rest seemed right I got 8A also *just sub in x=1
9/10 for that

You can believe

 

[mickstarify]

question 3 is A..
isn't it? conjugate base of z would be in the 4th quadrant? so multipy by 1 means it's in the first? O.O

what?
use the roots thing
so alpha + beta = -b/a
and alpha * beta = c/a

 

[Timske]

10/10

 

[hobozforlife]

question 3 is A..
isn't it? conjugate base of z would be in the 4th quadrant? so multipy by 1 means it's in the first? O.O

WUTT?!?!

 

[mickstarify]

Could someone explain 8, I was pretty confident with C but people are getting A, Why?

 

[studentcleo]

Why wouldn't 8 be B? Or is that just super silly

 

[TheOptimist]

Could someone explain 8, I was pretty confident with C but people are getting A, Why?

you test a point within the region, e.g. (3,0) the only conditions wich adhere to this point are in A. so A is correct, C is not

 

[RishBonjour]

you test a point within the region, e.g. (3,0) the only conditions wich adhere to this point are in A. so A is correct, C is not

yep. got A.

I hope 3u MC will be on this standard (relative to 3u) because some trial MC were just absurd, takes so many steps to get 1 mark.

 

[memo15]

For question 7 I substituted a whole heap of numbers as my x in the calculator and it kept giving me x^2 ?? So i put c...

 

[Rawf]

For question 7 I substituted a whole heap of numbers as my x in the calculator and it kept giving me x^2 ?? So i put c...

Loool wth
a^2 = e^(2x)
lne^(2x) = 2x (lne)
lne = 1, thus the answer is 2x

 

[memo15]

Loool wth
a^2 = e^(2x)
lne^(2x) = 2x (lne)
lne = 1, thus the answer is 2x

Yep. I feel soo stupid atm..

 

[Rawf]

Yep. I feel soo stupid atm..

You're saying you kept getting x^2 but you put C as the answer?
C is the correct answer.. C is 2x

 

[memo15]

Loll I am so messed up atm I'm sorry I meant I put x^2 as the answer.

 

[P.T.F.E]

Re: Compare Multiple Choice

Lolol it's really not that hard.
For the parabola equation, the shaded region is within it.. so you test (0,0) into the equation and find an inequality that satisfies it.
For the line, the shaded region has (3,0) in it, so you sub (3,0) into the equation and find one which satisfies it.

If the inequalities that satisfies the answer is correct.

+1, tested the same point aswell haha

 

[narenkumar]

Yeah, multiple choice was not hard.
It was straight forward.