- Sep 30, 2004
- Uni Grad
Share your multiple choice responses here
Case I is incorrect as you have to consider which person is excluded. this means that you have to multiple case 1 by 6, yielding 4020First consider the unrestricted case. We have six people going into four rooms and each person has four choices which gives 46.
Now subtract the cases where the restriction of 4 people per room is broken.
Case 1 - We have 5 people + 1 person. If we fix 5 people to be in the first room, the 1 person can go into the three other rooms. Similarly, if we fix the 5 people across the other rooms etc leading to 4x3 possibilities.
Case 2 - We have 6 people and there are four possibile rooms they can be in.
Altogether we get 46 - 4x3 - 4 = 4080