Section I - Multiple Choice (1 Viewer)

[Firmin]

10 was D, I'm pretty sure.

Yeah has to be because rate only increases when direction of velocity is equal to acceleration

1.D
2.B
3.A
4.A
5.C
6.D
7.B
8.B
9.C
10.D

 

[hjed]

Pretty sure 10 was B, positive acceleration = increasing speed. (although in this case it would have been decreasing velocity)

 

[CM07]

Yes 10 was d since
a=+2
v=-3
va=-6 since negative therefore decelerating/decreasing speed
Also as v=-3 (negative) therefore at that time particle was moving left of origin

Jfc I didn't think and used acceleration as speed fml.

im pretty sure 10 was b

remember velocity = speed WITH direction

and -acceleration means negative/going down
so i think it's B

I don't even know anymore. Still hoping it's (B).

 

[Recondit]

Im not sure on this anymore...
where a=+2 it means acceleration is acting to the right of the origin but since the particle is moving left to the origin shown by v=-3, it translates to decelerating moving to the left
+ acceleration doesn't apply to accelerating left and right but only right if you get what I mean

 

[Focus is Key]

Hoping its D because I guessed completely.

 

[spammer]

Well some one upload the paper. I forgot to grab mine from the room lol.

Alright if you insist...
View attachment HSC_2013_Mathematics.pdf

My responses
1 D
2 B
3 A
4 A
5 C
6 D
7 B
8 B
9 C
10 D

 

[joe_y]

drop kicks the answers are as follows;-

1. D
2. B
3. A
4. A
5. C
6. D
7. B
8. B
9. C
10. D

These are certain correct answer !!!!!!!!!!!!!!!!!

 

[Focus is Key]

drop kicks the answers are as follows;-

1. D
2. B
3. A
4. A
5. C
6. D
7. B
8. B
9. C
10. D

These are certain correct answer !!!!!!!!!!!!!!!!!

How do you know they're all correct?

 

[bedpotato]

I don't even know anymore. Still hoping it's (B).

If a > 0, the particle is travelling at an increasing speed.
If v < 0, the particle is travelling towards the left (or towards the origin).

For questions like: for what values of x is f(x) is increasing, isn't it when f'(x) > 0 ?

look at v as f(x) and a as f'(x)

Since a [f'(x)] is > 0, v [f(x)] is increasing. So the speed is increasing.

Therefore, the particle is moving towards the origin at an increasing rate (or speed, whatever it was).

 

[Alex Griffiths]

Congrats faggot, you got question 6 wrong... so much for calling everyone a drop kick

 

[Queenroot]

Congrats faggot, you got question 6 wrong... so much for calling everyone a drop kick

explain? Is it B?

 

[Alex Griffiths]

^ To be honest, i freaked out when I saw the question, but realised that there was a much simpler way of finding the answer (I stared at it for a few minutes): substitute values into the equation! The answer (if i remember correctly) is A - Substituting in x=pi/2 (and the other values in the graph), you find that y=o, meaning the first one is correct.

 

[hjed]

wolfram says D for question 6
http://www.wolframalpha.com/input/?i=y%3Dsin%282x%2Bpi%2F3%29

I did the multiple choice really fast and put B, because I missed that D had an intercept at -pi/6

 

[Focus is Key]

^ To be honest, i freaked out when I saw the question, but realised that there was a much simpler way of finding the answer (I stared at it for a few minutes): substitute values into the equation! The answer (if i remember correctly) is A - Substituting in x=pi/2 (and the other values in the graph), you find that y=o, meaning the first one is correct.

Please dear god let this be true; this is what I did but everyone else was posting different answers so I got worried.

 

[Alex Griffiths]

^ To be honest, i freaked out when I saw the question, but realised that there was a much simpler way of finding the answer (I stared at it for a few minutes): substitute values into the equation! The answer (if i remember correctly) is A - Substituting in x=pi/2 (and the other values in the graph), you find that y=o, meaning the first one is correct.

Note: you must be in radians

 

[dshah73]

1.D
2.B
3.A (trick question)
4. A
5. C
6. D
7. B
8. C
9.C
10. D

 

[hjed]

^ To be honest, i freaked out when I saw the question, but realised that there was a much simpler way of finding the answer (I stared at it for a few minutes): substitute values into the equation! The answer (if i remember correctly) is A - Substituting in x=pi/2 (and the other values in the graph), you find that y=o, meaning the first one is correct.

You remember incorrectly x=pi/2 is not on any of the graphs, but I get what you mean. If you know the formula it is much quicker to do it that way though

 

[Alex Griffiths]

You remember incorrectly x=pi/2 is not on any of the graphs, but I get what you mean. If you know the formula it is much quicker to do it that way though

Apologies, pi/3

 

[Alex Griffiths]

btw what was 14d? I had a stab at: a=4??

 

[Queenroot]

btw what was 14d? I had a stab at: a=4??

According to my friend it was 4.5 lol