No. If there are 31 days in October and there is an expected 8 rainy days and then the first day is rainy and they expect the second to be it becomes 8/31 x 7 (the remaining expected) x 30 (the remaining days). That's how in THEORY probability works. If you threw a coin 9 times and it was heads all the time the final chance would still be 1/2 for a tail. This question however doesn't follow that idea.
It is 8/31 x 7/30 hence A.
It is 8/31 x 7/30 hence A.