sequences and seriews (1 Viewer)

Average Boreduser · Dec 7, 2022

How would this be approached?

Drongoski · Dec 7, 2022

a)
$x^4-x^2 + 1 = x^4 + 2x^2 + 1 - 3x^2 = (x^2 + 1)^2 - (\sqrt 3 x)^2 \\ \\ = (x^2 +1 + \sqrt 3x )(x^2 + 1 - \sqrt 3 x)$

b)
$x^6 + 1 = (x^2)^3 + 1^3 = (x^2 + 1)(x^4-x^2 +1) \\ \\ =(x^2 + 1)(x^2+\sqrt 3 x + 1)(x^2 - \sqrt 3 x + 1)$

sequences and seriews (1 Viewer)

Average Boreduser

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