# series question. (1 Viewer)

#### Mdzabakly

##### Member
find the values of all pronumerals if these series are geometric
d) 1/4,t,1/9
e)y,2,6

#### Menomaths

##### Exaı̸̸̸̸̸̸̸̸lted Member
find the values of all pronumerals if these series are geometric
d) 1/4,t,1/9
e)y,2,6
Since they are geometric, (1/9)/t = t/(1/4)
Cross multiply you get t^2 = 1/36
Square root both sides you get 1/6
therefore t = 1/6

Since they are geometric, 6/2 =2/y
Cross multiply you get 6y = 4
Divide both sides by 6 you get y =4/6 =2/3

• Mdzabakly

#### ocatal

##### Active Member
d) t / (1/4) = (1/9) / t
Then cross multiply to get:
t^2 = 1 / 36
And solve for t:
t = 1 / 6

e) 2 / y = 6 / 2
2 / y = 3
And solve for y:
y = 2 / 3

#### ocatal

##### Active Member
Since they are geometric, (1/9)/t = t/(1/4)
Cross multiply you get t^2 = 1/36
Square root both sides you get 1/6
therefore t = 1/6

Since they are geometric, 6/2 =2/y
Cross multiply you get 6y = 4
Divide both sides by 6 you get y =4/6 =2/3
Beat me to it haha..

• Najji

#### Menomaths

##### Exaı̸̸̸̸̸̸̸̸lted Member
Beat me to it haha.. #### Menomaths

##### Exaı̸̸̸̸̸̸̸̸lted Member
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