M Mdzabakly Member Joined Apr 16, 2012 Messages 458 Gender Male HSC 2013 Jul 20, 2013 #1 find the values of all pronumerals if these series are geometric d) 1/4,t,1/9 e)y,2,6

Menomaths Exaı̸̸̸̸̸̸̸̸lted Member Joined Jul 9, 2013 Messages 2,373 Gender Male HSC 2013 Jul 20, 2013 #2 Mdzabakly said: find the values of all pronumerals if these series are geometric d) 1/4,t,1/9 e)y,2,6 Click to expand... Since they are geometric, (1/9)/t = t/(1/4) Cross multiply you get t^2 = 1/36 Square root both sides you get 1/6 therefore t = 1/6 Since they are geometric, 6/2 =2/y Cross multiply you get 6y = 4 Divide both sides by 6 you get y =4/6 =2/3

Mdzabakly said: find the values of all pronumerals if these series are geometric d) 1/4,t,1/9 e)y,2,6 Click to expand... Since they are geometric, (1/9)/t = t/(1/4) Cross multiply you get t^2 = 1/36 Square root both sides you get 1/6 therefore t = 1/6 Since they are geometric, 6/2 =2/y Cross multiply you get 6y = 4 Divide both sides by 6 you get y =4/6 =2/3

O ocatal Active Member Joined Sep 1, 2012 Messages 298 Gender Male HSC 2013 Jul 20, 2013 #3 d) t / (1/4) = (1/9) / t Then cross multiply to get: t^2 = 1 / 36 And solve for t: t = 1 / 6 e) 2 / y = 6 / 2 2 / y = 3 And solve for y: y = 2 / 3

d) t / (1/4) = (1/9) / t Then cross multiply to get: t^2 = 1 / 36 And solve for t: t = 1 / 6 e) 2 / y = 6 / 2 2 / y = 3 And solve for y: y = 2 / 3

O ocatal Active Member Joined Sep 1, 2012 Messages 298 Gender Male HSC 2013 Jul 20, 2013 #4 Menomaths said: Since they are geometric, (1/9)/t = t/(1/4) Cross multiply you get t^2 = 1/36 Square root both sides you get 1/6 therefore t = 1/6 Since they are geometric, 6/2 =2/y Cross multiply you get 6y = 4 Divide both sides by 6 you get y =4/6 =2/3 Click to expand... Beat me to it haha..

Menomaths said: Since they are geometric, (1/9)/t = t/(1/4) Cross multiply you get t^2 = 1/36 Square root both sides you get 1/6 therefore t = 1/6 Since they are geometric, 6/2 =2/y Cross multiply you get 6y = 4 Divide both sides by 6 you get y =4/6 =2/3 Click to expand... Beat me to it haha..

Menomaths Exaı̸̸̸̸̸̸̸̸lted Member Joined Jul 9, 2013 Messages 2,373 Gender Male HSC 2013 Jul 20, 2013 #5 ocatal said: Beat me to it haha.. Click to expand...

Menomaths Exaı̸̸̸̸̸̸̸̸lted Member Joined Jul 9, 2013 Messages 2,373 Gender Male HSC 2013 Jul 20, 2013 #6 The moment when you find your real life friend on bos....