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Simple Circle Geometry question (1 Viewer)

bawd

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Draw it from my explanation if you can:

AMB and CMB are two intersecting chords of a circle, centre O. If OM bisects angle AMC internally, prove that AB = CB.

I tried by proving congruent triangles ADM and CMB, but it didn't work lol.

Thanks to whoever can help. :)
 

bawd

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That's how the question is worded, but I'll reword as to how I understand it.

Two chords AB and and CD intersect at a point M in a circle with O as the centre. The line OM (the line from the centre to the intersection point of the chords AB, CD) bisects angle AMC. Prove that AB = CD.
 

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