Simple Harmonic Motion (1 Viewer)

WEMG

Member
Joined
Aug 15, 2009
Messages
118
Gender
Undisclosed
HSC
2011
Fitzpatrick 25C, Q16
A particle moving with SHM starts from rest at x=5 and after 2 seconds reaches x=2.5.
Find:
i) an expression for the displacement at time t > or = 0
 
K

khorne

Guest
Ok, v = 0, x = 5, t = 0 is the starting point, at a maximum, so the equation is x = acos(nt + O)
But since it's starting directly at t = 0, it is x = acos(nt)
t = 0, x = 5
x = 5cos(nt)
t = 2, x = 2.5
1/2 = cos(2n)
solve for n, etc.
 

WEMG

Member
Joined
Aug 15, 2009
Messages
118
Gender
Undisclosed
HSC
2011
omg, 'starts at rest' lmao, thanks korn
 
Last edited by a moderator:

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top