MedVision ad

simple maximisation/minisation question (1 Viewer)

kooltrainer

New Member
Joined
Jun 17, 2006
Messages
659
Gender
Male
HSC
2008
a) Draw the region between the parabola y^2 = 4ax and latus rectum x=a .
b) Hence, find the dimensions of the rectangle with maximum area in this region.

thx =)
 

kooltrainer

New Member
Joined
Jun 17, 2006
Messages
659
Gender
Male
HSC
2008
ehh thx, but i got another problem .. a locus one

Q: p(x,y) lies on the line y=4x+3 . show tht M (midpoint of OP) has co ordinates (x/2 , 1/2(4x+3)) hence , find the locus of M
 

ssglain

Member
Joined
Sep 18, 2006
Messages
445
Location
lost in a Calabi-Yau
Gender
Female
HSC
2007
SoulSearcher said:
I must say your handwriting has kept up amazingly well after all these months after school. Mine's has gone to the shits :eek:
I swear, this does not resemble my pre-HSC handwriting.
 

SoulSearcher

Active Member
Joined
Oct 13, 2005
Messages
6,757
Location
Entangled in the fabric of space-time ...
Gender
Male
HSC
2007
Co-ordinates of O - (0, 0) [Taken this as an assumption, but unless defined otherwise, O is usually taken to be the point of origin on the Cartesian plane]
Co-ordinates of P - (x1, y1), y = 4x+3

When x = x1, y = 4x1+3, hence y1 = 4x1+3

Therefore co-ordinates of M (midpoint of OP) is ([0+x1]/2, [0+y1]/2)
= (x1/2, y1/2)
= (x1/2, [4x1+3]/2)

To find the locus of M, let
x = x1/2 ... (1)
y = [4x1+3]/2 ... (2)

Hence, from (1),
2x = x1 ... (3)

Substitute (3) into (2),
y = [4(2x)+3]/2
y = [8x + 3]/2, locus of M

ssglain said:
I swear, this does not resemble my pre-HSC handwriting.
Still better than mine :)
 

ssglain

Member
Joined
Sep 18, 2006
Messages
445
Location
lost in a Calabi-Yau
Gender
Female
HSC
2007
SoulSearcher said:
Co-ordinates of O - (0, 0) [Taken this as an assumption, but unless defined otherwise, O is usually taken to be the point of origin on the Cartesian plane]
Co-ordinates of P - (x1, y1), y = 4x+3

When x = x1, y = 4x1+3, hence y1 = 4x1+3

Therefore co-ordinates of M (midpoint of OP) is ([0+x1]/2, [0+y1]/2)
= (x1/2, y1/2)
= (x1/2, [4x1+3]/2)

To find the locus of M, let
x = x1/2 ... (1)
y = [4x1+3]/2 ... (2)

Hence, from (1),
2x = x1 ... (3)

Substitute (3) into (2),
y = [4(2x)+3]/2
y = [8x + 3]/2, locus of M

Still better than mine :)
You beat me to it. Haha. ;)
 

SoulSearcher

Active Member
Joined
Oct 13, 2005
Messages
6,757
Location
Entangled in the fabric of space-time ...
Gender
Male
HSC
2007
ssglain said:
You beat me to it. Haha. ;)
I'm amazed I still know this stuff, I last learnt this around 2 years ago, and probably did this type of question only a couple times last year :uhhuh:

kooltrainer, I definitely recommend that you take on sslgain as a tutor, she is obviously talented at maths and will help you improve in the subject greatly :)
 

kooltrainer

New Member
Joined
Jun 17, 2006
Messages
659
Gender
Male
HSC
2008
ssglain said:
Since you go to FSHS, you mustn't live far from Burwood. How about I tutor you?
i'l think abt it.. thing is, it takes me 45 min to get to FSHS, its gona take me 1 hr to get to burwood
 

ssglain

Member
Joined
Sep 18, 2006
Messages
445
Location
lost in a Calabi-Yau
Gender
Female
HSC
2007
kooltrainer said:
i'l think abt it.. thing is, it takes me 45 min to get to FSHS, its gona take me 1 hr to get to burwood
We can have our session on a school day (once term recommences, of course) - it only takes about 10 mins by train from Petersham to Burwood.
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top