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small question (1 Viewer)

Thread starter Ragerunner
Start date Mar 28, 2004

Ragerunner

Your friendly HSC guide

#1

Find all complex sixth roots of -4(1+ squareroot of 3)

Can someone please do the working out for this?

Thanks.

M

martin310015

Member

#2

what does complex sixth root mean...

Grey Council

Legend

#3

[ -4( 1 + squareroot of 3)]<sup>1/6</sup>

McLake

The Perfect Nerd

#4

This is beyond HSC syllabus, so moved ...

Affinity

Active Member

#5

modulus is 8
argument is -2Pi/3

so one of the complex sixth root is sqrt(2)*cis(-pi/9)
the others can be found by adding Pi/3 to the argument

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