Sum of Coefifcients in Binomial? (1 Viewer)

Watsername

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How would you do this question:

Find the sum of the cooeficients in (8a - 5b)^17

The answer is huge
 

haboozin

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Watsername said:
How would you do this question:

Find the sum of the cooeficients in (8a - 5b)^17

The answer is huge

8^17 - 17c1x8^16x5 + 17c2x8^15x5^2 - ... .... - 5^17

i dont really see any easier way of doing this? :s
what a silly question.
 

KFunk

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One thing you could do to make life easier is to take a factor of 8<sup>17</sup> out:

8<sup>17</sup>[1 - <sup>17</sup>C<sub>1</sub>(5/8) + <sup>17</sup>C<sub>2</sub>(5/8)<sup>2</sup> - <sup>17</sup>C<sub>3</sub>(5/8)<sup>3</sup> + ... - (5/8)<sup>17</sup>]

If you kept (5/8) on the [ANS] - previous answer button then you could save your self a lot of button bashing. What a smelly question.
 

Dreamerish*~

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KFunk said:
One thing you could do to make life easier is to take a factor of 8<sup>17</sup> out:

8<sup>17</sup>[1 - <sup>17</sup>C<sub>1</sub>(5/8) + <sup>17</sup>C<sub>2</sub>(5/8)<sup>2</sup> - <sup>17</sup>C<sub>3</sub>(5/8)<sup>3</sup> + ... - (5/8)<sup>17</sup>]

If you kept (5/8) on the [ANS] - previous answer button then you could save your self a lot of button bashing. What a smelly question.
That's really smart. Why am I not surprised it came from you? :rolleyes:
 

Watsername

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yeh, thats exactly what i started writing out, and then I thought I must be missing something you surely going to make a mistake on your calculator during that
 

haboozin

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Watsername said:
yeh, thats exactly what i started writing out, and then I thought I must be missing something you surely going to make a mistake on your calculator during that

thats why you would never be asked this question...

you might be asked one that the sum of coefficients are zero
 

currysauce

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Watsername said:
How would you do this question:

Find the sum of the cooeficients in (8a - 5b)^17

The answer is huge
Isn't there a rule for sum of the coefficients

(a+x) ^ n is 2^n
 

zozo

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i wouldnt worry about it too much, its a beast of a questoin, the HSC just wouldnt ask it... at least not to the power of 17... maybe 4.

if you did ever get presented with a question like that in HSC, you'd be better to throw down some working out and move on, cause its only gonna be worth 1 or 2 marks tops... why waste 5 min when you milk 5 more marks in that time.
 

acmilan

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Its really quite simple, and Templar explained it. Just make a and b = 1
 

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