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Surds Help Please (1 Viewer)

davidbarnes

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When dividing surds, would
72 -
18 +
8

be

3
8 -
2?
 
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davidbarnes

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When their are multiple indices to work with, do you multiply or add these?

E.g.

(10^2)^4 --- Does this become 10^8 or 10^6?

(10^3)^2
 

davidbarnes

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When writing 30758 as products of prime factors, can anyone please tell me what this is. I know how to do these, and can do others fine, although keep getting the answer 2^2 x 7 x 13^3 for this one, which is wrong.
 

davidbarnes

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What is the keyboard equivalent sign for the root sign?
 
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You can use Root(x) or anything else you like, we're not dumb, so we'll understand it :p

Your images are being hotlink protected, could you make other arrangements for them?

Also, your questions seem all over the place, gime (and others) a minute. You should also edit current posts, instead of making new ones directly after your original one.
 

acmilan

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(102)4 = 108. You multiply in that case

And to find prime factors, easiest way is trial and error, eg:

30758 / 2 = 15379, so 2 is a factor

Now find prime factors of 15379

15379 / 2 = 7644.5, so 2 isnt a factor
15379 / 3 = 5126.33, so 3 isnt a factor
15379 / 5 = 3057.8, so 5 isnt a factor
15379 / 7 = 2184.14, so 7 isnt a factor
15379 / 11 = 1309.91, so 11 isnt a factor
15379 / 13 = 1183, so 13 is a factor

Now find factors of 1183 (you start from 13 since anything lower cant be factors)
1183 / 13 = 91, so 13 is a factor again

factors of 91:
91 / 13 = 7, so 13 is a factor again

Now 7 is left over, which is prime, so thats the last prime factor

So 30758 = 2 x 7 x 133

You got an extra 2 somewhere in yours
 
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1.

sqr72 - sqr18 +sqr8
You'd simply the roots as much as you can,

sqr72 - sqr18 +sqr8 = 6sqr2 - 3sqr2 + 2sqr2
sqr72 - sqr18 +sqr8 = 5sqr2


2.

If you're multiplying or dividing the bases, you add or subtract the bases, respectively.
(x^1 * x^11 ) / x^6 = x^2
Because 1+11=12, divided by 6 = 2

If it's a power to the power, you multiply the bases - eg.
(x^4)^2 = x^8
Because 4*2 = 8


Rest been covered I think.
 

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